Work the Shell

Working with Command Arguments

Dave Taylor

Issue #262, February 2016

getopt—the right way to parse starting arguments in your shell script.

In my last article, I went interstellar and created a multi-planet time translator, allowing you to learn just how old you'd be if you lived on Saturn or Pluto. So in this article, I want to head back to a more fundamental aspect of shell scripting: working with command arguments.

I suspect that most shell scripts go through an evolution with their command flags, actually starting out with none, then maybe one or two parsed in a sloppy fashion, finally upgraded to a proper implementation of getopt, and then, perhaps, even being completely rewritten as a C++ or Ruby program as the complexity keeps inexorably increasing.

The really easy way to parse a starting flag, of course, is just to use a conditional statement:

if [ "$1" = "-a" ]; then
  flaga=1
fi

There are a couple problems with this approach, however, not the least of which is that it ends up taking a fair amount of space in the code. Because to be proper, the full sequence also would include flaga=0 before the conditional, because (repeat after me) you never can assume that the shell will correctly instantiate the value of a newly defined variable.

The other problem is that after this code sequence, the command parameters are out of sync: $1 is still either possibly the starting flag value (-a) or another argument or value that the user has specified.

To make this a bit more logical, let's imagine a shell script that's a wrapper to something like the terrific curl: give it a URL, and it'll grab that content and save it to the local directory as a file. Add the imagined -a flag, and it'll also include progress information. So, a typical usage might look like this:

getpage.sh -a http://www.linuxjournal.com/index.html

In this situation, a number of command parameter variables are going to be instantiated as the shell script is invoked, notably $# = 2, $0 = getpage.sh, $1 = -a and $2 = http://www.linuxjournal.com/index.html.

Where I always get tripped up is that $# is the number of arguments, not the total number of words in the command. Therefore, if this script is invoked without any arguments at all, $# seems like it should be 1 (what about the command name?), but actually it's 0.

This goes back to the dawn of UNIX development actually, and it's known as the “0 index problem”. In arrays, the first value is referenced as being in slot 0, or array[0]. For some developers, that makes complete sense, and for others, it can be confusing. Indeed, I've seen C programs where the writer ignores the first slot entirely and indexes starting at 1, not 0.

With that in mind, after the conditional has been used to check for the -a flag in the first variable space ($1), what really needs to happen is that all the positional variables above this one (for example, $2, $3 and so on) need to shift down a spot. Ideally, after the conditional, $1 contains the URL value regardless of whether the starting flag was specified.

That way, the next statement block in the script safely can assume that $1 will be the URL and not have to test redundantly to see if it's still -a.

This is done with the shift command, and so, here's the proper way to test conditionally for an optional variable in a shell script:

flaga=0
if [ "$1" = "-a" ]; then
  flaga=1
  shift
fi

That works exactly as you'd hope, but leads to the next question: what happens if the flag has an optional value that the user can specify? In the case of this curl script, perhaps the flag is something like -o output file.

That's actually an easy addition to the above code:

outputspecified=0
if [ "$1" = "-o" ]; then
  outputspecified=1
  outputfilename="$2"
  shift 2
fi

As you can see, shift takes a single numeric argument that reflects how many slots you want to have everything cascade. It's easy to see if you consider the positional values before and after the above code block:

$ sh getpage.sh -0 test.html SomeURL
$# = 3
$1 = -a
$2 = test.html
$3 = SomeURL
-----
$# = 1
$1 = SomeURL
$2 =
$3 =

Initially, all three positional variables are set, and the arg count ($#) is 3, as makes sense given the command invocation. But after the shift 2, everything's moved down two slots, and the arg count also is decremented two, as you can see above.

Now, what if your development of the script hits a juncture where you realize that it'd be useful to have three different starting arguments, one of which indeed takes an argument?

Dealing with Lots of Starting Flags

Even two flags can be a pain, because it'd be terrible code that would force the user to specify them in order, but without that, -a, -c and -o could require you to test for all three, parse and shift, then test for all three again, parse and shift, then test for all three one more time. That would be a nightmare, and I haven't even mentioned how those pesky users have a tendency to combine flags too, so would your script properly parse -ac -o or -oc -a too?

Enter getopt.

The getopt command is going to become your best friend if you're building complex user-facing scripts, no question. It basically works by extracting all the optional flags and parameters, then lets you parse through them in a uniform manner.

The standard usage is to break down combined args with an invocation of getopt, then use the set command to replace the existing starting flags with the new, neater args, then run through a loop, parsing them one by one.

Yes, this is easier just to demonstrate, so let me show you the command flag parsing segment from a different production script. This particular command has three possible starting flags, -n, -p and -t.

The first step in the script is to have getopt normalize whatever the user has specified:

args=$(getopt np:t $*)

Comparing this statement with the usage error below, you can see that arg 1 to getopt is a list of all acceptable flags, with : denoting those flags that have a required additional argument if the flag is specified—easy enough.

Now the status variable $? can be tested: if it's non-zero, there was an error in parsing the flags, and in most scripts, it's time to fail out with a usage statement:

if [ $? != 0] ; then
  echo \
    "Usage: $(basename $0) {-p SFX} {-n} {-t} PTN NEWPTN"
  echo "    -n   sequentially number matching files"
  echo "    -p   use specified suffix SFX for filenames"
  echo "    -t   test only - don't execute resultant cmds"
  exit 0
fi

You'll often see scripts that have the usage sequence pushed into a separate function to keep the code clean. Also, note the use of $(basename $0) in the first echo. That's a handy trick to compensate for the fact that most of the time $0 is going to be the full name of the script, including path. So tapping basename is just for aesthetics!

Finally, the statement that does the real work:

set -- $args

Now all the positional parameters are neatly organized and ready to parse, something that's traditionally done with a case statement wrapped in a for loop (no difference from an enigma wrapped in a dilemma, of course). It looks like this:

for i
do
  case "$i"
  in
   -n ) renumber=1 ; shift ;;
   -p ) fixpng=1   ; sfx=$2 ; shift 2 ;;
   -t ) doit=0     ; shift ;;
 esac
done

I have a particular style with the semicolons in my case statements, mostly just to ensure that I use the needed ;; sequence to terminate each of the individual conditionals, but otherwise, it should be easy to understand.

The only thing missing from this code fragment is something I alluded to earlier. What is it?

And, that's it for this article. Now, go back to your latest shell script, and just for practice, go ahead and add some optional starting flags and parse them with getopt.

Dave Taylor has been hacking shell scripts since the dawn of the computer era. Well, not really, but still, 30 years is a long time! He's the author of the popular Wicked Cool Shell Scripts and Teach Yourself Unix in 24 Hours (new edition just released!). He can be found on Twitter as @DaveTaylor and more generally at his tech site: www.AskDaveTaylor.com.